Prove that the circle `x^2 + y^2-6x-4y+9=0` bisects the circumference of the circle `x^2 +

Name: Prove that the circle `x^2 + y^2-6x-4y+9=0` bisects the circumference of the circle `x^2 +
Uploaded: 2025-01-21T11:07:13+03:00
Duration: 5 min 55 s
Description: Prove that the circle `x^2 + y^2-6x-4y+9=0` bisects the circumference of the circle `x^2 +

Prove that the circle `x^2 + y^2-6x-4y+9=0` bisects the circumference of the circle `x^2 + y^2 - 8x-6y+23=0`

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Prove that the circle `x^2 + y^2-6x-4y+9=0` bisects the circumference of the circle `x^2 + y^2 - 8x-6y+23=0`

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